What is the value of sin(-pi/4)+cos(-pi/4) ?

The value of sin(-pi/4)+cos(-pi/4) is 0

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sin(-pi/4)+cos(-pi/4)

sin (- \frac{π}{4}) + cos (- \frac{π}{4})

0

Solution steps

sin (- \frac{π}{4}) + cos (- \frac{π}{4})

Use the following property:

cos (- x) = cos (x)

cos (- \frac{π}{4}) = cos (\frac{π}{4})

= sin (- \frac{π}{4}) + cos (\frac{π}{4})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{π}{4}) = - sin (\frac{π}{4})

= - sin (\frac{π}{4}) + cos (\frac{π}{4})

Use the following trivial identity:

sin (\frac{π}{4}) = \frac{2}{2}

sin (\frac{π}{4})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

Use the following trivial identity:

cos (\frac{π}{4}) = \frac{2}{2}

cos (\frac{π}{4})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= - \frac{2}{2} + \frac{2}{2}

Simplify

= 0

tan (- 22 5^{\circ}) + tan (40 5^{\circ})

\frac{sin ( 4 0 ^{\circ} )}{sin ( 2 0 ^{\circ} )}

\frac{- 313.3}{sin ( 6 0 ^{\circ} )}

\frac{sin ( 2 )}{( 2 )}

\frac{1 + sin ( \frac{π}{2} )}{1 - cos ( 2 π )}

What is the value of sin(-pi/4)+cos(-pi/4) ?
The value of sin(-pi/4)+cos(-pi/4) is 0