What is the value of sin(60)(sqrt(3))/2 ?

The value of sin(60)(sqrt(3))/2 is 3/4

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sin(60)(sqrt(3))/2

sin (6 0^{\circ}) \frac{3}{2}

\frac{3}{4}

Decimal Notation

0.75

Solution steps

sin (6 0^{\circ}) \frac{3}{2}

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{3}{2} \cdot \frac{3}{2}

Simplify

\frac{3}{2} \cdot \frac{3}{2} : \frac{3}{4}

\frac{3}{2} \cdot \frac{3}{2}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 3}{2 \cdot 2}

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{3}{4}

= \frac{3}{4}

- \frac{1}{6} cos^{3} (π)

\frac{sec ( 12 0 ^{\circ} ) + cot ( 22 5 ^{\circ} ) + cos ( 31 5 ^{\circ} )}{sin ( 27 0 ^{\circ} )}

arccos (0.174)

sin (34 0^{\circ}) cos (12 0^{\circ}) - cos (34 0^{\circ}) sin (12 0^{\circ})

sin (arccot (cos (arctan (1))))

What is the value of sin(60)(sqrt(3))/2 ?
The value of sin(60)(sqrt(3))/2 is 3/4