What is the value of 35tan(0)-15.022sec^2(0)+1 ?

The value of 35tan(0)-15.022sec^2(0)+1 is -7011/500

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35tan(0)-15.022sec^2(0)+1

35 tan (0) - 15.022 sec^{2} (0) + 1

- \frac{7011}{500}

Decimal Notation

- 14.022

Solution steps

35 tan (0) - 15.022 sec^{2} (0) + 1

= 35 tan (0) - \frac{7511}{500} sec^{2} (0) + 1

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

Use the following trivial identity:

sec (0) = 1

sec (0)

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 1

= 35 \cdot 0 - \frac{7511}{500} \cdot 1^{2} + 1

Simplify

35 \cdot 0 - \frac{7511}{500} \cdot 1^{2} + 1 : - \frac{7011}{500}

35 \cdot 0 - \frac{7511}{500} \cdot 1^{2} + 1

Apply rule

1^{a} = 1

1^{2} = 1

= 35 \cdot 0 - 1 \cdot \frac{7511}{500} + 1

Apply rule

0 \cdot a = 0

= 0 - 1 \cdot \frac{7511}{500} + 1

Multiply:

\frac{7511}{500} \cdot 1 = \frac{7511}{500}

= 0 - \frac{7511}{500} + 1

Add the numbers:

0 + 1 = 1

= - \frac{7511}{500} + 1

Convert element to fraction:

1 = \frac{1 \cdot 500}{500}

= \frac{1 \cdot 500}{500} - \frac{7511}{500}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 500 - 7511}{500}

1 \cdot 500 - 7511 = - 7011

1 \cdot 500 - 7511

Multiply the numbers:

1 \cdot 500 = 500

= 500 - 7511

Subtract the numbers:

500 - 7511 = - 7011

= - 7011

= \frac{- 7011}{500}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7011}{500}

= - \frac{7011}{500}

cos (arcsec (2))

0.05 \cdot cos (22.91 \cdot 0.07)

2 cos (- \frac{π}{2}) + \frac{π}{2}

- cos (1 6^{\circ})

cos (22. 6^{\circ})

What is the value of 35tan(0)-15.022sec^2(0)+1 ?
The value of 35tan(0)-15.022sec^2(0)+1 is -7011/500