What is the value of 10*6*cos(120) ?

The value of 10*6*cos(120) is -30

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106cos(120)

10 \cdot 6 \cdot cos (12 0^{\circ})

- 30

Solution steps

10 \cdot 6 cos (12 0^{\circ})

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

cos (12 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{1}{2}

= 10 \cdot 6 (- \frac{1}{2})

Simplify

10 \cdot 6 (- \frac{1}{2}) : - 30

10 \cdot 6 (- \frac{1}{2})

Remove parentheses:

(- a) = - a

= - 10 \cdot 6 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 10 \cdot 6}{2}

Multiply the numbers:

1 \cdot 10 \cdot 6 = 60

= - \frac{60}{2}

Divide the numbers:

\frac{60}{2} = 30

= - 30

= - 30

cos (2 arctan (\frac{9}{40}))

\frac{5}{cos ( 4 2 ^{\circ} )}

\frac{sin ^{2} ( 1 )}{1 ^{2}}

sin (1.25)

\frac{sin ( 12 0 ^{\circ} ) cos ( 21 0 ^{\circ} ) tan ( 31 5 ^{\circ} ) cos ( 2 7 ^{\circ} )}{sin ( 6 3 ^{\circ} ) cos ( 54 0 ^{\circ} )}