What is the value of (cos^2(0))/2 ?

The value of (cos^2(0))/2 is 1/2

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(cos^2(0))/2

\frac{cos ^{2} ( 0 )}{2}

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\frac{cos ^{2} ( 0 )}{2}

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= \frac{1 ^{2}}{2}

Simplify

= \frac{1}{2}

arcsin (\frac{3 \cdot 0.54 \cdot 1 0 ^{- 6}}{\frac{1}{200000}})

\frac{sec ( 3 7 ^{\circ} ) + tan ( 3 7 ^{\circ} )}{sec ( 1 6 ^{\circ} ) + tan ( 1 6 ^{\circ} )}

- sin (- \frac{5 π}{3})

∣ sin (2) ∣

\frac{2 sin ( 6 0 ^{\circ} )}{cot ( 3 0 ^{\circ} ) - 4 sin ( 4 5 ^{\circ} )}