What is the value of cos(150)-sin(240)+tan(300) ?

The value of cos(150)-sin(240)+tan(300) is -sqrt(3)

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cos(150)-sin(240)+tan(300)

cos (15 0^{\circ}) - sin (24 0^{\circ}) + tan (30 0^{\circ})

- 3

Solution steps

cos (15 0^{\circ}) - sin (24 0^{\circ}) + tan (30 0^{\circ})

Use the following trivial identity:

cos (15 0^{\circ}) = - \frac{3}{2}

Rewrite using trig identities:

sin (24 0^{\circ}) = - \frac{3}{2}

Rewrite using trig identities:

tan (30 0^{\circ}) = - 3

= - \frac{3}{2} - (- \frac{3}{2}) - 3

Simplify

= - 3

arctan (\frac{- \frac{3}{2}}{\frac{1}{2}})

arccos (- 0.05)

cos (0.99)

sin (3 0^{\circ}) \cdot 80

cos^{8} (0)

What is the value of cos(150)-sin(240)+tan(300) ?
The value of cos(150)-sin(240)+tan(300) is -sqrt(3)