What is the value of cos(arccot(-1)) ?

The value of cos(arccot(-1)) is -(sqrt(2))/2

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cos(arccot(-1))

cos (arccot (- 1))

- \frac{2}{2}

Decimal Notation

- 0.70710 \dots

Solution steps

cos (arccot (- 1))

Rewrite using trig identities:

cos (arccot (- 1)) = \frac{( - 1 ) 1 + ( - 1 ) ^{2}}{1 + ( - 1 ) ^{2}}

Use the following identity:

cos (arccot (x)) = \frac{x 1 + x ^{2}}{1 + x ^{2}}

= \frac{( - 1 ) 1 + ( - 1 ) ^{2}}{1 + ( - 1 ) ^{2}}

= \frac{( - 1 ) 1 + ( - 1 ) ^{2}}{1 + ( - 1 ) ^{2}}

Simplify

= - \frac{2}{2}

\frac{cos ^{3} ( 0 )}{3} - cos (0)

cos (\frac{π}{25})

arcsin (\frac{1.33 \cdot sin ( 5 8 ^{\circ} )}{1.52})

sin (15 1^{\circ})

- 8 cos (\frac{5 π}{6})

What is the value of cos(arccot(-1)) ?
The value of cos(arccot(-1)) is -(sqrt(2))/2