What is the value of (arccos(1/2))/3 ?

The value of (arccos(1/2))/3 is pi/9

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(arccos(1/2))/3

\frac{arccos ( \frac{1}{2} )}{3}

\frac{π}{9}

Decimal Notation

20

Solution steps

\frac{arccos ( \frac{1}{2} )}{3}

Use the following trivial identity:

arccos (\frac{1}{2}) = \frac{π}{3}

arccos (\frac{1}{2})

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{3}

= \frac{\frac{π}{3}}{3}

Simplify

\frac{\frac{π}{3}}{3} : \frac{π}{9}

\frac{\frac{π}{3}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{π}{9}

= \frac{π}{9}

128 + 127.5 sin (\frac{2 π}{16} \cdot 4)

arccot (\frac{8}{15})

4 \cdot sin (\frac{π}{2})

10 sin (π^{0.29})

csc (\frac{π}{3}) - cos (\frac{π}{4})