What is the value of (sec(pi/6))^2 ?

The value of (sec(pi/6))^2 is 4/3

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(sec(pi/6))^2

(sec (\frac{π}{6}))^{2}

\frac{4}{3}

Decimal Notation

1.33333 \dots

Solution steps

(sec (\frac{π}{6}))^{2}

= sec^{2} (\frac{π}{6})

Use the following trivial identity:

sec (\frac{π}{6}) = \frac{2 3}{3}

sec (\frac{π}{6})

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= \frac{2 3}{3}

= (\frac{2 3}{3})^{2}

Simplify

(\frac{2 3}{3})^{2} : \frac{4}{3}

(\frac{2 3}{3})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 3 ) ^{2}}{3 ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(23)^{2} = 2^{2} (3)^{2}

= \frac{2 ^{2} ( 3 ) ^{2}}{3 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{2 ^{2} \cdot 3}{3 ^{2}}

Cancel the common factor:

3

= \frac{2 ^{2}}{3}

2^{2} = 4

= \frac{4}{3}

= \frac{4}{3}

arccos (cos (4.13))

cos (40.8 9^{\circ})

2 sin (1.1 π)

161 cos (1 4^{\circ}) + \frac{555 sin ( 1 4 ^{\circ} )}{8} - \frac{21 cos ( 1 4 ^{\circ} )}{4}

- \frac{26}{3} sin (3 \cdot \frac{2}{3} π) + 3 cos (3 \cdot \frac{2}{3} π) - \frac{2}{9}