What is the value of -pisin(-pi) ?

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-pisin(-pi)

- π sin (- π)

0

Solution steps

- π sin (- π)

Rewrite using trig identities:

sin (- π) = 0

sin (- π)

Use the following property:

sin (- x) = - sin (x)

sin (- π) = - sin (π)

= - sin (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= - 0

Simplify

= 0

= - π 0

Simplify

= 0

cos (3.15)

(\frac{1}{2}) sec (8 0^{\circ}) - 2 sin (7 0^{\circ})

arctan (\frac{4}{19})

cos (5 7^{\circ}) cos (3 3^{\circ}) - sin (5 7^{\circ}) sin (3 3^{\circ})

arctan (\frac{1}{2}) - arctan (- \frac{1}{2})