What is the value of tan^2(30)+cos^2(60) ?

The value of tan^2(30)+cos^2(60) is 7/12

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tan^2(30)+cos^2(60)

tan^{2} (3 0^{\circ}) + cos^{2} (6 0^{\circ})

\frac{7}{12}

Solution steps

tan^{2} (3 0^{\circ}) + cos^{2} (6 0^{\circ})

Use the following trivial identity:

tan (3 0^{\circ}) = \frac{3}{3}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

= (\frac{3}{3})^{2} + (\frac{1}{2})^{2}

Simplify

(\frac{3}{3})^{2} + (\frac{1}{2})^{2} : \frac{7}{12}

= \frac{7}{12}

\frac{sin ( 6 0 ^{\circ} ) cos ( 3 0 ^{\circ} )}{tan ( 4 5 ^{\circ} )}

\frac{1}{e ^{0.01} ( sin ( 0.01 ) + cos ( 0.01 ) )}

\frac{37. 2 ^{2} sin ( 2 \cdot 14.1 )}{9.8}

\frac{π}{2} - arctan (2)

arccos (\frac{2}{85})

What is the value of tan^2(30)+cos^2(60) ?
The value of tan^2(30)+cos^2(60) is 7/12