What is the value of cos(arcsin(-1/5)) ?

The value of cos(arcsin(-1/5)) is (2sqrt(6))/5

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cos(arcsin(-1/5))

cos (arcsin (- \frac{1}{5}))

\frac{2 6}{5}

Decimal Notation

0.97979 \dots

Solution steps

cos (arcsin (- \frac{1}{5}))

Rewrite using trig identities:

cos (arcsin (- \frac{1}{5})) = 1 - (- \frac{1}{5})^{2}

Use the following identity:

cos (arcsin (x)) = 1 - x^{2}

= 1 - (- \frac{1}{5})^{2}

= 1 - (- \frac{1}{5})^{2}

Simplify

= \frac{2 6}{5}

cosh (ln (2)) + sinh (ln (2))

18 0^{\circ} - arcsin (\frac{182 sin ( 4 0 ^{\circ} )}{255})

5 \cdot sin (2 5^{\circ})

tan (23. 2^{\circ})

cos (- \frac{25 π}{4})

What is the value of cos(arcsin(-1/5)) ?
The value of cos(arcsin(-1/5)) is (2sqrt(6))/5