What is the value of 3cos(0^2)-18(0)^2sin(0^2)-8(0)^4cos(0^2) ?

The value of 3cos(0^2)-18(0)^2sin(0^2)-8(0)^4cos(0^2) is 3

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3cos(0^2)-18(0)^2sin(0^2)-8(0)^4cos(0^2)

3 cos (0^{2}) - 18 (0)^{2} sin (0^{2}) - 8 (0)^{4} cos (0^{2})

3

Solution steps

3 cos (0^{2}) - 18 (0)^{2} sin (0^{2}) - 8 (0)^{4} cos (0^{2})

= 3 cos (0^{2}) - 18 \cdot 0^{2} sin (0^{2}) - 8 \cdot 0^{4} cos (0^{2})

Simplify

= 3 cos (0)

Use the following trivial identity:

cos (0) = 1

= 3 \cdot 1

Simplify

= 3

sin (\frac{4}{5} - \frac{5}{13})

2 sin (\frac{3 π}{7}) cos (\frac{3 π}{7})

3 sin (0)

46 sin (6 0^{\circ})

csc^{2} (\frac{3 π}{4})

What is the value of 3cos(0^2)-18(0)^2sin(0^2)-8(0)^4cos(0^2) ?
The value of 3cos(0^2)-18(0)^2sin(0^2)-8(0)^4cos(0^2) is 3