What is the value of (sin(45))^2-2cos(30) ?

The value of (sin(45))^2-2cos(30) is 1/2-sqrt(3)

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(sin(45))^2-2cos(30)

(sin (4 5^{\circ}))^{2} - 2 cos (3 0^{\circ})

\frac{1}{2} - 3

Solution steps

(sin (4 5^{\circ}))^{2} - 2 cos (3 0^{\circ})

= sin^{2} (4 5^{\circ}) - 2 cos (3 0^{\circ})

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

Use the following trivial identity:

cos (3 0^{\circ}) = \frac{3}{2}

= (\frac{2}{2})^{2} - 2 \cdot \frac{3}{2}

Simplify

(\frac{2}{2})^{2} - 2 \cdot \frac{3}{2} : \frac{1}{2} - 3

= \frac{1}{2} - 3

sin (arccos (\frac{1}{5}))

\frac{sin ( 4 5 ^{\circ} )}{1.41}

tanh (ln (3)) - tanh (0)

cos^{2} (0.6)

cos (4 0^{\circ}) \cdot 8

What is the value of (sin(45))^2-2cos(30) ?
The value of (sin(45))^2-2cos(30) is 1/2-sqrt(3)