What is the value of arccos(sin(-(11pi)/4)) ?

The value of arccos(sin(-(11pi)/4)) is (3pi)/4

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arccos(sin(-(11pi)/4))

arccos (sin (- \frac{11 π}{4}))

\frac{3 π}{4}

Solution steps

arccos (sin (- \frac{11 π}{4}))

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{11 π}{4}) = - sin (\frac{11 π}{4})

= arccos (- sin (\frac{11 π}{4}))

sin (\frac{11 π}{4}) = sin (\frac{3 π}{4})

= arccos (- sin (\frac{3 π}{4}))

Rewrite using trig identities:

sin (\frac{3 π}{4}) = - sin (\frac{5 π}{4})

= arccos (- (- sin (\frac{5 π}{4})))

Simplify

= arccos (sin (\frac{5 π}{4}))

Rewrite using trig identities:

sin (\frac{5 π}{4}) = cos (\frac{3 π}{4})

= arccos (cos (\frac{3 π}{4}))

Use the inverse trig property:

\frac{3 π}{4}

= \frac{3 π}{4}

arcsech (0)

sin (68.9 6^{\circ})

32 π^{2} sin (1.5 π)

\frac{( 7.51 ) ^{2} sin ( 2 ( 15 ) )}{9.4}

(1 + sin (π))^{\frac{1}{t a n ( π )}}

What is the value of arccos(sin(-(11pi)/4)) ?
The value of arccos(sin(-(11pi)/4)) is (3pi)/4