What is the value of sin(30)+cos(60)-tan(45) ?

The value of sin(30)+cos(60)-tan(45) is 0

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sin(30)+cos(60)-tan(45)

sin (3 0^{\circ}) + cos (6 0^{\circ}) - tan (4 5^{\circ})

0

Solution steps

sin (3 0^{\circ}) + cos (6 0^{\circ}) - tan (4 5^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

tan (4 5^{\circ}) = 1

= \frac{1}{2} + \frac{1}{2} - 1

Simplify

\frac{1}{2} + \frac{1}{2} - 1 : 0

= 0

arctan (887)

sin (\frac{7}{12} π) - cos (\frac{π}{12})

cos (41.4 1^{\circ})

arcsin (\frac{1}{1195})

arctan (\frac{15}{40})

What is the value of sin(30)+cos(60)-tan(45) ?
The value of sin(30)+cos(60)-tan(45) is 0