What is the value of sin(120)+cos(120) ?

The value of sin(120)+cos(120) is (sqrt(3)-1)/2

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sin(120)+cos(120)

sin (12 0^{\circ}) + cos (12 0^{\circ})

\frac{3 - 1}{2}

Solution steps

sin (12 0^{\circ}) + cos (12 0^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

= \frac{3}{2} - \frac{1}{2}

Simplify

\frac{3}{2} - \frac{1}{2} : \frac{3 - 1}{2}

= \frac{3 - 1}{2}

arctan (\frac{- 5}{- 3})

sin (59.4 9^{\circ})

arccos (0.9235)

cos (31 5^{\circ}) - sin (24 0^{\circ}) + sin (22 5^{\circ})

3.8 cos (\frac{18 π}{13} - \frac{12 π}{13})

What is the value of sin(120)+cos(120) ?
The value of sin(120)+cos(120) is (sqrt(3)-1)/2