What is the value of sqrt(3)((2pi)/3)+2cos((2pi)/3) ?

The value of sqrt(3)((2pi)/3)+2cos((2pi)/3) is (2sqrt(3)pi)/3-1

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sqrt(3)((2pi)/3)+2cos((2pi)/3)

3 (\frac{2 π}{3}) + 2 cos (\frac{2 π}{3})

\frac{2 3 π}{3} - 1

Decimal Notation

2.62759 \dots

Solution steps

3 (\frac{2 π}{3}) + 2 cos (\frac{2 π}{3})

= 3 \frac{2 π}{3} + 2 cos (\frac{2 π}{3})

Use the following trivial identity:

cos (\frac{2 π}{3}) = - \frac{1}{2}

cos (\frac{2 π}{3})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{1}{2}

= 3 \frac{2 π}{3} + 2 (- \frac{1}{2})

Simplify

3 \frac{2 π}{3} + 2 (- \frac{1}{2}) : \frac{2 3 π}{3} - 1

3 \frac{2 π}{3} + 2 (- \frac{1}{2})

Remove parentheses:

(- a) = - a

= 3 \frac{2 π}{3} - 2 \cdot \frac{1}{2}

3 \frac{2 π}{3} = \frac{2 3 π}{3}

3 \frac{2 π}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 π 3}{3}

2 \cdot \frac{1}{2} = 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= \frac{2 3 π}{3} - 1

= \frac{2 3 π}{3} - 1

- 6 sin (\frac{2 π}{0.8} (0.5 - 0.2)) + 15

sin^{2} (12 0^{\circ}) - cos^{2} (12 0^{\circ})

\frac{9.8}{0.0272 \cdot cos ^{2} ( - 0.78 )}

2 sin^{2} (1)

9.8 sin (3 7^{\circ})

What is the value of sqrt(3)((2pi)/3)+2cos((2pi)/3) ?
The value of sqrt(3)((2pi)/3)+2cos((2pi)/3) is (2sqrt(3)pi)/3-1