What is the value of 4arcsec(sqrt(4))-sqrt(4-1) ?

The value of 4arcsec(sqrt(4))-sqrt(4-1) is (4pi)/3-sqrt(3)

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4arcsec(sqrt(4))-sqrt(4-1)

4 arcsec (4) - 4 - 1

\frac{4 π}{3} - 3

Decimal Notation

140.76

Solution steps

4 arcsec (4) - 4 - 1

Use the following trivial identity:

arcsec (4) = \frac{π}{3}

arcsec (4)

x 1 \frac{2 3}{3} 22 - 2 - 2 - \frac{2 3}{3} - 1 arcsec (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} π arcsec (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} 18 0^{\circ}

= \frac{π}{3}

= 4 \cdot \frac{π}{3} - 4 - 1

Simplify

4 \cdot \frac{π}{3} - 4 - 1 : \frac{4 π}{3} - 3

4 \cdot \frac{π}{3} - 4 - 1

Multiply

4 \cdot \frac{π}{3} : \frac{4 π}{3}

4 \cdot \frac{π}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 4}{3}

= \frac{4 π}{3} - 4 - 1

Subtract the numbers:

4 - 1 = 3

= \frac{4 π}{3} - 3

= \frac{4 π}{3} - 3

(12) (\frac{π}{8})^{2} - 2 csc^{2} (\frac{π}{4})

2 + 2 sin (\frac{2 π}{3})

\frac{π}{2} csc (\frac{π}{2}) - \frac{1}{2} cot (\frac{π}{2})

1 - 2 sin (\frac{π}{2})

72.4 sin (3 2^{\circ})

What is the value of 4arcsec(sqrt(4))-sqrt(4-1) ?
The value of 4arcsec(sqrt(4))-sqrt(4-1) is (4pi)/3-sqrt(3)