What is the value of sqrt((1+cos(60))/2) ?

The value of sqrt((1+cos(60))/2) is (sqrt(3))/2

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sqrt((1+cos(60))/2)

\frac{1 + cos ( 6 0 ^{\circ} )}{2}

\frac{3}{2}

Decimal Notation

0.86602 \dots

Solution steps

\frac{1 + cos ( 6 0 ^{\circ} )}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{1 + \frac{1}{2}}{2}

Simplify

\frac{1 + \frac{1}{2}}{2} : \frac{3}{2}

\frac{1 + \frac{1}{2}}{2}

\frac{1 + \frac{1}{2}}{2} = \frac{3}{4}

\frac{1 + \frac{1}{2}}{2}

Join

1 + \frac{1}{2} : \frac{3}{2}

1 + \frac{1}{2}

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 + 1}{2}

1 \cdot 2 + 1 = 3

1 \cdot 2 + 1

Multiply the numbers:

1 \cdot 2 = 2

= 2 + 1

Add the numbers:

2 + 1 = 3

= 3

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{3}{4}

= \frac{3}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{3}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{3}{2}

= \frac{3}{2}

2 sin (2 1^{\circ}) cos (2 1^{\circ})

sin (20. 2^{\circ})

cos (\frac{16}{20})

3 sec (0) tan (0)

2 \cdot (\frac{3}{tan ( 1 8 ^{\circ} )} \cdot 30) + 240

What is the value of sqrt((1+cos(60))/2) ?
The value of sqrt((1+cos(60))/2) is (sqrt(3))/2