What is the value of 0.96*sin(30) ?

The value of 0.96*sin(30) is 12/25

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0.96*sin(30)

0.96 \cdot sin (3 0^{\circ})

\frac{12}{25}

Decimal Notation

0.48

Solution steps

0.96 sin (3 0^{\circ})

= \frac{24}{25} sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{24}{25} \cdot \frac{1}{2}

Simplify

\frac{24}{25} \cdot \frac{1}{2} : \frac{12}{25}

\frac{24}{25} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= \frac{12}{25}

= \frac{12}{25}

\frac{0.93}{sin ( 13 2 ^{\circ} )}

cos (- 96 0^{\circ})

cos (\frac{3 π}{4}) - i \cdot sin (\frac{3 π}{4})

arcsin (\frac{6}{4})

sin^{2} (10 0^{\circ})