What is the value of arctan(-(12)/(4sqrt(3))) ?

The value of arctan(-(12)/(4sqrt(3))) is -pi/3

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arctan(-(12)/(4sqrt(3)))

arctan (- \frac{12}{4 3})

- \frac{π}{3}

Decimal Notation

- 60

Solution steps

arctan (- \frac{12}{4 3})

Simplify:

- \frac{12}{4 3} = - 3

- \frac{12}{4 3}

Divide the numbers:

\frac{12}{4} = 3

= \frac{3}{3}

Apply radical rule:

3 = 3^{\frac{1}{2}}

= \frac{3}{3 ^{\frac{1}{2}}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{3 ^{1}}{3 ^{\frac{1}{2}}} = 3^{1 - \frac{1}{2}}

= 3^{1 - \frac{1}{2}}

Subtract the numbers:

1 - \frac{1}{2} = \frac{1}{2}

= 3^{\frac{1}{2}}

Apply radical rule:

3^{\frac{1}{2}} = 3

= - 3

= arctan (- 3)

Use the following property:

arctan (- x) = - arctan (x)

arctan (- 3) = - arctan (3)

= - arctan (3)

Use the following trivial identity:

arctan (3) = \frac{π}{3}

arctan (3)

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{3}

= - \frac{π}{3}

6 cos (7 π)

38 cos (6 0^{\circ})

- 50 \cdot 9.81 \cdot sin (3 7^{\circ}) \cdot 3

2 (- 2.19) cos (2 (- 2.19)) - ((- 2.19) + 1)^{2}

sin (\frac{5}{3}) π

What is the value of arctan(-(12)/(4sqrt(3))) ?
The value of arctan(-(12)/(4sqrt(3))) is -pi/3