What is the value of -cos(pi/2)+(cos^3(pi/2))/3 ?

The value of -cos(pi/2)+(cos^3(pi/2))/3 is 0

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-cos(pi/2)+(cos^3(pi/2))/3

- cos (\frac{π}{2}) + \frac{cos ^{3} ( \frac{π}{2} )}{3}

0

Solution steps

- cos (\frac{π}{2}) + \frac{cos ^{3} ( \frac{π}{2} )}{3}

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (\frac{π}{2})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= - 0 + \frac{0 ^{3}}{3}

Simplify

= 0

\frac{sin ( - π )}{4}

\frac{sin ( 1 )}{( 1 )}

\frac{( 0 ) ^{2} - 1}{cos ( 0 )}

e^{- π} sin (π)

\frac{sin ( 4 )}{1 + cos ( 4 )}

What is the value of -cos(pi/2)+(cos^3(pi/2))/3 ?
The value of -cos(pi/2)+(cos^3(pi/2))/3 is 0