What is the value of sin(11)cos(49)+cos(11)sin(49) ?

The value of sin(11)cos(49)+cos(11)sin(49) is (sqrt(3))/2

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sin(11)cos(49)+cos(11)sin(49)

sin (1 1^{\circ}) cos (4 9^{\circ}) + cos (1 1^{\circ}) sin (4 9^{\circ})

\frac{3}{2}

Decimal Notation

0.86602 \dots

Solution steps

sin (1 1^{\circ}) cos (4 9^{\circ}) + cos (1 1^{\circ}) sin (4 9^{\circ})

Rewrite using trig identities:

sin (6 0^{\circ})

sin (1 1^{\circ}) cos (4 9^{\circ}) + cos (1 1^{\circ}) sin (4 9^{\circ})

Use the Angle Sum identity:

sin (s) cos (t) + cos (s) sin (t) = sin (s + t)

= sin (1 1^{\circ} + 4 9^{\circ})

Simplify

= sin (6 0^{\circ})

= sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{3}{2}

- 4 sin (2 (0))

sin (\frac{π}{6}) - tan (\frac{π}{4}) - cos (\frac{π}{3})

cos (3 0^{\circ} + 6 0^{\circ})

arccos (\frac{7}{20})

tan (\frac{10}{3})

What is the value of sin(11)cos(49)+cos(11)sin(49) ?
The value of sin(11)cos(49)+cos(11)sin(49) is (sqrt(3))/2