What is the value of -500cos(45) ?

The value of -500cos(45) is -250sqrt(2)

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-500cos(45)

- 500 cos (4 5^{\circ})

- 2502

Decimal Notation

- 353.55339 \dots

Solution steps

- 500 cos (4 5^{\circ})

Use the following trivial identity:

cos (4 5^{\circ}) = \frac{2}{2}

cos (4 5^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= - 500 \cdot \frac{2}{2}

Simplify

- 500 \cdot \frac{2}{2} : - 2502

- 500 \cdot \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{2 \cdot 500}{2}

Divide the numbers:

\frac{500}{2} = 250

= - 2502

= - 2502

\frac{tan ( 8 0 ^{\circ} )}{tan ( 10 0 ^{\circ} )}

\frac{sin ( \frac{35}{25} ) π}{6}

arccos (\frac{6}{22})

ln (1) \cdot (1)^{0} + e^{0} \cdot 2 \cdot sin (0) + cos (0) \cdot 2 \cdot e^{0}

2 cos^{2} (3 7^{\circ}) - 1