What is the value of -cos(4 pi/2) ?

The value of -cos(4 pi/2) is -1

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-cos(4 pi/2)

- cos (4 \frac{π}{2})

- 1

Solution steps

- cos (4 \cdot \frac{π}{2})

Rewrite using trig identities:

cos (4 \cdot \frac{π}{2}) = 1

cos (4 \cdot \frac{π}{2})

Simplify:

4 \cdot \frac{π}{2} = 2 π

4 \cdot \frac{π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 π

= cos (2 π)

cos (2 π) = cos (0)

cos (2 π)

Rewrite

2 π

2 π + 0

= cos (2 π + 0)

Apply the periodicity of

cos

cos (x + 2 π) = cos (x)

cos (2 π + 0) = cos (0)

= cos (0)

= cos (0)

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= 1

= - 1

arctan (\frac{16}{32})

- 2 (3.27) - e^{- 0.54} sin (3.27)

2 \cdot cos (\frac{3 π}{2})

sec (3 0^{\circ}) - csc (2 4^{\circ})

arctan (\frac{11}{19})