What is the value of sin(120)+cos(210)-tan(225) ?

The value of sin(120)+cos(210)-tan(225) is -1

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sin(120)+cos(210)-tan(225)

sin (12 0^{\circ}) + cos (21 0^{\circ}) - tan (22 5^{\circ})

- 1

Solution steps

sin (12 0^{\circ}) + cos (21 0^{\circ}) - tan (22 5^{\circ})

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

Rewrite using trig identities:

cos (21 0^{\circ}) = - \frac{3}{2}

Rewrite using trig identities:

tan (22 5^{\circ}) = 1

= \frac{3}{2} - \frac{3}{2} - 1

Simplify

= - 1

- 1 sin (\frac{π}{2})

1 cos (2 5^{\circ})

arctan (\frac{- 1}{2.26})

arctan^{\frac{1}{3}} (\frac{( 2.5 )}{1.5})

\frac{12 sin ( 3 2 ^{\circ} )}{7}

What is the value of sin(120)+cos(210)-tan(225) ?
The value of sin(120)+cos(210)-tan(225) is -1