What is the value of ((9arccos(cos(1))+4)^{3/2}-8)/(27) ?

The value of ((9arccos(cos(1))+4)^{3/2}-8)/(27) is (13*13^{1/2}-8)/(27)

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((9arccos(cos(1))+4)^{3/2}-8)/(27)

\frac{( 9 arccos ( cos ( 1 ) ) + 4 ) ^{\frac{3}{2}} - 8}{27}

\frac{13 \cdot 1 3 ^{\frac{1}{2}} - 8}{27}

Solution steps

\frac{( 9 arccos ( cos ( 1 ) ) + 4 ) ^{\frac{3}{2}} - 8}{27}

Rewrite using trig identities:

arccos (cos (1)) = 1

= \frac{( 9 \cdot 1 + 4 ) ^{\frac{3}{2}} - 8}{27}

Simplify

\frac{( 9 \cdot 1 + 4 ) ^{\frac{3}{2}} - 8}{27} : \frac{13 \cdot 1 3 ^{\frac{1}{2}} - 8}{27}

= \frac{13 \cdot 1 3 ^{\frac{1}{2}} - 8}{27}

sin (9.6)

\frac{tan ( 1 )}{2}

sin (- \frac{π}{2}) + 1

\frac{sin ( 6 0 ^{\circ} )}{11}

cos (- \frac{1}{4} π)

What is the value of ((9arccos(cos(1))+4)^{3/2}-8)/(27) ?
The value of ((9arccos(cos(1))+4)^{3/2}-8)/(27) is (13*13^{1/2}-8)/(27)