What is the value of (sin(pi/2))/((pi/2)) ?

The value of (sin(pi/2))/((pi/2)) is 2/pi

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(sin(pi/2))/((pi/2))

\frac{sin ( \frac{π}{2} )}{( \frac{π}{2} )}

\frac{2}{π}

Decimal Notation

0.63661 \dots

Solution steps

\frac{sin ( \frac{π}{2} )}{( \frac{π}{2} )}

= \frac{sin ( \frac{π}{2} )}{\frac{π}{2}}

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= \frac{1}{\frac{π}{2}}

Simplify

= \frac{2}{π}

tan (\frac{12}{19})

π - arccos (\frac{1}{2})

\frac{12000}{tan ( 2 8 ^{\circ} )} + \frac{12000}{tan ( 4 6 ^{\circ} )}

arctan (1.55)

arctan (1.54)

What is the value of (sin(pi/2))/((pi/2)) ?
The value of (sin(pi/2))/((pi/2)) is 2/pi