What is the value of (4+cos(2*(45)))*10^{-3} ?

The value of (4+cos(2*(45)))*10^{-3} is 1/250

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(4+cos(2(45)))10^{-3}

(4 + cos (2 \cdot (4 5^{\circ}))) \cdot 1 0^{- 3}

\frac{1}{250}

Solution steps

(4 + cos (2 (4 5^{\circ}))) \cdot 1 0^{- 3}

= (4 + cos (2 \cdot 4 5^{\circ})) \cdot 1 0^{- 3}

Rewrite using trig identities:

cos (2 \cdot 4 5^{\circ}) = 0

= (4 + 0) \cdot 1 0^{- 3}

Simplify

(4 + 0) \cdot 1 0^{- 3} : \frac{1}{250}

= \frac{1}{250}

\frac{110 \cdot 2}{π} \cdot (1 + cos (785 4^{\circ}))

arcsin (- \frac{4}{7})

\frac{0.1 cos ( 0.1 ) - sin ( 0.1 )}{0.1 - sin ( 0.1 )}

2 \cdot sin (5 3^{\circ})

\frac{50 sin ( 1 5 ^{\circ} )}{400}

What is the value of (4+cos(2*(45)))*10^{-3} ?
The value of (4+cos(2*(45)))*10^{-3} is 1/250