What is the value of arctan(cot(6)) ?

The value of arctan(cot(6)) is (3pi-12)/2

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arctan(cot(6))

arctan (cot (6))

\frac{3 π - 12}{2}

Solution steps

arctan (cot (6))

Rewrite using trig identities:

cot (6) = tan (\frac{π - 12}{2})

= arctan (tan (\frac{π - 12}{2}))

Use the inverse trig property:

\frac{3 π - 12}{2}

= \frac{3 π - 12}{2}

\frac{1.54}{9.81 \cdot sin ( 1 8 ^{\circ} )}

1.6 (sin (1) + cos (1))

\frac{2 \cdot 0.0351}{2.7} \cdot ln (0.84 cos (7.85 \cdot 2.7))

4 cos (π)

arctan (0.853)