What is the value of 2cos^2(240)+3sin(240) ?

The value of 2cos^2(240)+3sin(240) is (1-3sqrt(3))/2

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2cos^2(240)+3sin(240)

2 cos^{2} (24 0^{\circ}) + 3 sin (24 0^{\circ})

\frac{1 - 3 3}{2}

Solution steps

2 cos^{2} (24 0^{\circ}) + 3 sin (24 0^{\circ})

Rewrite using trig identities:

cos^{2} (24 0^{\circ}) = 1 - sin^{2} (24 0^{\circ})

= 2 (1 - sin^{2} (24 0^{\circ})) + 3 sin (24 0^{\circ})

Rewrite using trig identities:

sin (24 0^{\circ}) = - \frac{3}{2}

= 2 1 - (- \frac{3}{2})^{2} + 3 (- \frac{3}{2})

Simplify

2 1 - (- \frac{3}{2})^{2} + 3 (- \frac{3}{2}) : \frac{1 - 3 3}{2}

= \frac{1 - 3 3}{2}

cot (arcsin (\frac{6}{7}))

- cos (21 0^{\circ}) - sin (31 5^{\circ})

\frac{1}{2} sec (2) tan (2) + \frac{1}{2} ln (sec (2) + tan (2))

sin (\frac{arcsin ( \frac{3}{5} )}{2})

15 sin (\frac{π}{4})

What is the value of 2cos^2(240)+3sin(240) ?
The value of 2cos^2(240)+3sin(240) is (1-3sqrt(3))/2