What is the value of -3cos(-pi/6)-4tan(-pi/6) ?

The value of -3cos(-pi/6)-4tan(-pi/6) is -(sqrt(3))/6

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-3cos(-pi/6)-4tan(-pi/6)

- 3 cos (- \frac{π}{6}) - 4 tan (- \frac{π}{6})

- \frac{3}{6}

Solution steps

- 3 cos (- \frac{π}{6}) - 4 tan (- \frac{π}{6})

Use the following property:

tan (- x) = - tan (x)

tan (- \frac{π}{6}) = - tan (\frac{π}{6})

= - 3 cos (- \frac{π}{6}) - 4 (- tan (\frac{π}{6}))

Use the following property:

cos (- x) = cos (x)

cos (- \frac{π}{6}) = cos (\frac{π}{6})

= - 3 cos (\frac{π}{6}) - 4 (- tan (\frac{π}{6}))

Simplify

= - 3 cos (\frac{π}{6}) + 4 tan (\frac{π}{6})

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

Use the following trivial identity:

tan (\frac{π}{6}) = \frac{3}{3}

= - 3 \cdot \frac{3}{2} + 4 \cdot \frac{3}{3}

Simplify

- 3 \cdot \frac{3}{2} + 4 \cdot \frac{3}{3} : - \frac{3}{6}

= - \frac{3}{6}

e^{l n (5)} arctan (5 e^{- l n (5)})

sin (- \frac{π}{7})

cot (152.410 3^{\circ})

5 (cos (\frac{π}{6}) + i sin (\frac{π}{6}))

(cos (\frac{π}{3}))^{2} + (sin (\frac{π}{3}))^{2}

What is the value of -3cos(-pi/6)-4tan(-pi/6) ?
The value of -3cos(-pi/6)-4tan(-pi/6) is -(sqrt(3))/6