What is the value of -1/2 tan(2/5*pi/2) ?

The value of -1/2 tan(2/5*pi/2) is -(sqrt(2)(sqrt(5)-1)sqrt(5-\sqrt{5)})/8

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-1/2 tan(2/5*pi/2)

- \frac{1}{2} tan (\frac{2}{5} \cdot \frac{π}{2})

- \frac{2 ( 5 - 1 ) 5 - 5}{8}

Solution steps

- \frac{1}{2} tan (\frac{2}{5} \cdot \frac{π}{2})

Simplify:

\frac{2}{5} \cdot \frac{π}{2} = \frac{π}{5}

- \frac{1}{2} tan (\frac{π}{5}) = - \frac{tan ( \frac{π}{5} )}{2}

= - \frac{tan ( \frac{π}{5} )}{2}

Rewrite using trig identities:

tan (\frac{π}{5}) = \frac{2 ( 5 - 1 ) 5 - 5}{4}

= - \frac{\frac{2 ( 5 - 1 ) 5 - 5}{4}}{2}

Simplify

- \frac{\frac{2 ( 5 - 1 ) 5 - 5}{4}}{2} : - \frac{2 ( 5 - 1 ) 5 - 5}{8}

= - \frac{2 ( 5 - 1 ) 5 - 5}{8}

arctan (\frac{57.9}{90})

cos (5.2)

- sin (\frac{π}{4}) + 2 cos (\frac{π}{4})

arccos (\frac{1 3 ^{2} + 1 3 ^{2} + 7 ^{2}}{2 ( 13 ) ( 13 )})

sin (\frac{π}{3}) + 1

What is the value of -1/2 tan(2/5*pi/2) ?
The value of -1/2 tan(2/5*pi/2) is -(sqrt(2)(sqrt(5)-1)sqrt(5-\sqrt{5)})/8