What is the value of 2sin(30)+cos(60) ?

The value of 2sin(30)+cos(60) is 3/2

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2sin(30)+cos(60)

2 sin (3 0^{\circ}) + cos (6 0^{\circ})

\frac{3}{2}

Solution steps

2 sin (3 0^{\circ}) + cos (6 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

= 2 \cdot \frac{1}{2} + \frac{1}{2}

Simplify

2 \cdot \frac{1}{2} + \frac{1}{2} : \frac{3}{2}

= \frac{3}{2}

1200 cos (5 0^{\circ})

cos (\frac{- 3 π}{8})

sin (24 8^{\circ})

arctan (- \frac{1}{( 3.1305 ) ( 10 )})

arcsin (\frac{18}{22})