What is the value of 20sin(150) ?

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20sin(150)

20 sin (15 0^{\circ})

10

Solution steps

20 sin (15 0^{\circ})

Use the following trivial identity:

sin (15 0^{\circ}) = \frac{1}{2}

sin (15 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= 20 \cdot \frac{1}{2}

Simplify

20 \cdot \frac{1}{2} : 10

20 \cdot \frac{1}{2}

Convert element to fraction:

20 = \frac{20}{1}

= \frac{1}{2} \cdot \frac{20}{1}

Cross-cancel common factor:

2

= \frac{10}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 10

= 10

lo g_{10} (sin (45.20249 9^{\circ}))

sin (8 0^{\circ}) sin (5) + cos (8 0^{\circ}) cos (5)

\frac{( 30 ) ^{2} sin ^{2} ( 3 0 ^{\circ} )}{2 \cdot 9.8 1 ^{2}}

tan (4 1^{\circ}) \cdot 3

\frac{5.78}{tan ( 3 8 ^{\circ} )}