What is the value of 1/3 (-8cos(0)-(tan^2(0))/2) ?

The value of 1/3 (-8cos(0)-(tan^2(0))/2) is -8/3

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1/3 (-8cos(0)-(tan^2(0))/2)

\frac{1}{3} (- 8 cos (0) - \frac{tan ^{2} ( 0 )}{2})

- \frac{8}{3}

Solution steps

\frac{1}{3} (- 8 cos (0) - \frac{tan ^{2} ( 0 )}{2})

Use the following trivial identity:

cos (0) = 1

Use the following trivial identity:

tan (0) = 0

= \frac{1}{3} (- 8 \cdot 1 - \frac{0 ^{2}}{2})

Simplify

\frac{1}{3} (- 8 \cdot 1 - \frac{0 ^{2}}{2}) : - \frac{8}{3}

= - \frac{8}{3}

30 sin (5 5^{\circ})

arcsin (\frac{3 3}{6})

\frac{arcsin ( \frac{1}{3} ) - arcsin ( - \frac{1}{3} )}{600}

450 sin (7 5^{\circ})

sinh (\frac{7}{17})

What is the value of 1/3 (-8cos(0)-(tan^2(0))/2) ?
The value of 1/3 (-8cos(0)-(tan^2(0))/2) is -8/3