What is the value of 2sinh^2(10) ?

The value of 2sinh^2(10) is ((e^{20}-1)^2)/(2e^{20)}

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2sinh^2(10)

2 sinh^{2} (10)

\frac{( e ^{20} - 1 ) ^{2}}{2 e ^{20}}

Solution steps

2 sinh^{2} (10)

Rewrite using trig identities:

sinh (10) = \frac{e ^{20} - 1}{2 e ^{10}}

= 2 (\frac{e ^{20} - 1}{2 e ^{10}})^{2}

Simplify

2 (\frac{e ^{20} - 1}{2 e ^{10}})^{2} : \frac{( e ^{20} - 1 ) ^{2}}{2 e ^{20}}

= \frac{( e ^{20} - 1 ) ^{2}}{2 e ^{20}}

cos (1) - (1) e^{1}

7 \cdot cos (5.8 \cdot π)

15 \cdot tan (3 0^{\circ})

\frac{36 sin ( 6 1 ^{\circ} )}{20}

500 cos (12 0^{\circ})

What is the value of 2sinh^2(10) ?
The value of 2sinh^2(10) is ((e^{20}-1)^2)/(2e^{20)}