What is the value of sech(1) ?

The value of sech(1) is (2e)/(e^2+1)

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sech(1)

sech (1)

\frac{2 e}{e ^{2} + 1}

Decimal Notation

0.64805 \dots

Solution steps

sech (1)

Use the Hyperbolic identity:

sech (x) = \frac{2}{e ^{x} + e ^{- x}}

= \frac{2}{e ^{1} + e ^{- 1}}

\frac{2}{e ^{1} + e ^{- 1}} = \frac{2 e}{e ^{2} + 1}

\frac{2}{e ^{1} + e ^{- 1}}

Apply rule

a^{1} = a

e^{1} = e

= \frac{2}{e + e ^{- 1}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{2}{e + \frac{1}{e}}

Join

e + \frac{1}{e} : \frac{e ^{2} + 1}{e}

e + \frac{1}{e}

Convert element to fraction:

e = \frac{ee}{e}

= \frac{ee}{e} + \frac{1}{e}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{ee + 1}{e}

ee + 1 = e^{2} + 1

ee + 1

ee = e^{2}

ee

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ee = e^{1 + 1}

= e^{1 + 1}

Add the numbers:

1 + 1 = 2

= e^{2}

= e^{2} + 1

= \frac{e ^{2} + 1}{e}

= \frac{2}{\frac{e ^{2} + 1}{e}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{2 e}{e ^{2} + 1}

= \frac{2 e}{e ^{2} + 1}

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