What is the general solution for arccos(e^{-x})= pi/3 ?

The general solution for arccos(e^{-x})= pi/3 is x=ln(2)

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arccos(e^{-x})= pi/3

arccos (e^{- x}) = \frac{π}{3}

x = ln (2)

Solution steps

arccos (e^{- x}) = \frac{π}{3}

Apply trig inverse properties

e^{- x} = \frac{1}{2}

Solve

e^{- x} = \frac{1}{2} : x = ln (2)

x = ln (2)

cos (θ) = - \frac{11}{170}

2 cos^{2} (θ) - 7 cos (θ) + 3 = 0, 0 \leq θ \leq 2 π

4 sin (x) cos (x) + 2 sin (x) - 2 cos (x) = 1

sin (x) cos^{2} (x) = sin (x)

3 sin (x) cos (x) = cos^{2} (x)

What is the general solution for arccos(e^{-x})= pi/3 ?
The general solution for arccos(e^{-x})= pi/3 is x=ln(2)