What is the general solution for 7cos(2t)=3 ?

The general solution for 7cos(2t)=3 is t=(1.12788…)/2+pin,t=pi-(1.12788…)/2+pin

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7cos(2t)=3

7 cos (2 t) = 3

t = \frac{1.12788 \dots}{2} + πn, t = π - \frac{1.12788 \dots}{2} + πn

Solution steps

7 cos (2 t) = 3

Divide both sides by

7

cos (2 t) = \frac{3}{7}

Apply trig inverse properties

2 t = arccos (\frac{3}{7}) + 2 πn, 2 t = 2 π - arccos (\frac{3}{7}) + 2 πn

Solve

2 t = arccos (\frac{3}{7}) + 2 πn : t = \frac{arccos ( \frac{3}{7} )}{2} + πn

Solve

2 t = 2 π - arccos (\frac{3}{7}) + 2 πn : t = π - \frac{arccos ( \frac{3}{7} )}{2} + πn

t = \frac{arccos ( \frac{3}{7} )}{2} + πn, t = π - \frac{arccos ( \frac{3}{7} )}{2} + πn

Show solutions in decimal form

t = \frac{1.12788 \dots}{2} + πn, t = π - \frac{1.12788 \dots}{2} + πn

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What is the general solution for 7cos(2t)=3 ?
The general solution for 7cos(2t)=3 is t=(1.12788…)/2+pin,t=pi-(1.12788…)/2+pin