What is the general solution for sin^2(x)-cos(x)+1=0 ?

The general solution for sin^2(x)-cos(x)+1=0 is x=2pin

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sin^2(x)-cos(x)+1=0

sin^{2} (x) - cos (x) + 1 = 0

x = 2 πn

Solution steps

sin^{2} (x) - cos (x) + 1 = 0

Rewrite using trig identities

2 - cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = - 2, cos (x) = 1

cos (x) = - 2 :

No Solution

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

tan (2 x) = 2 sin (x)

sin (θ) - cos (θ) = \frac{2 + 3}{2}

w, s (t) = sin (a t) cos (wt)

2 sin (2 x) \cdot cos (3 x) + cos (3 x) = 0

4 sin (x) - 4 cos (x) = 2

What is the general solution for sin^2(x)-cos(x)+1=0 ?
The general solution for sin^2(x)-cos(x)+1=0 is x=2pin