What is the general solution for 2arctan(1/2)=arccos(x) ?

The general solution for 2arctan(1/2)=arccos(x) is x= 3/5

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2arctan(1/2)=arccos(x)

2 arctan (\frac{1}{2}) = arccos (x)

x = \frac{3}{5}

Solution steps

2 arctan (\frac{1}{2}) = arccos (x)

Switch sides

arccos (x) = 2 arctan (\frac{1}{2})

Apply trig inverse properties

x = \frac{3}{5}

2 sin^{2} (x) - 7 sin (x) = - 3

sin (\frac{x}{2}) + sin (\frac{x}{2}) = sin (x)

cos (x) + 2 sin^{2} (x) = 1

15 cos (x) - 5 = 4 cos (x)

sin (θ) + cos (θ) = \frac{2 + 3}{2}

What is the general solution for 2arctan(1/2)=arccos(x) ?
The general solution for 2arctan(1/2)=arccos(x) is x= 3/5