What is the general solution for 2(tan(θ)+3)=5+tan(θ) ?

The general solution for 2(tan(θ)+3)=5+tan(θ) is θ=(3pi)/4+pin

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2(tan(θ)+3)=5+tan(θ)

2 (tan (θ) + 3) = 5 + tan (θ)

θ = \frac{3 π}{4} + πn

Solution steps

2 (tan (θ) + 3) = 5 + tan (θ)

Solve by substitution

tan (θ) = - 1

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

sin^{2} (x) = \frac{( 9 m - 8 )}{2}

\frac{5}{2} cos (2 x) - \frac{1}{2} = 3 sin (x)

cos (π + x) = \frac{1}{2}

(tan (x) - 4) (16 sin^{2} (x) - 1) = 0

sec^{2} (x) = 2 sin^{2} (x) + tan^{2} (x)

What is the general solution for 2(tan(θ)+3)=5+tan(θ) ?
The general solution for 2(tan(θ)+3)=5+tan(θ) is θ=(3pi)/4+pin