What is the general solution for sin^2(x)+2cos(x)-2=0 ?

The general solution for sin^2(x)+2cos(x)-2=0 is x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)+2cos(x)-2=0

sin^{2} (x) + 2 cos (x) - 2 = 0

x = 2 πn

Solution steps

sin^{2} (x) + 2 cos (x) - 2 = 0

Rewrite using trig identities

- 1 - cos^{2} (x) + 2 cos (x) = 0

Solve by substitution

cos (x) = 1

cos (x) = 1 : x = 2 πn

Combine all the solutions

x = 2 πn

2 sin (x) = sec (x)

2 - sin (x) = 2 cos^{2} (x)

- sin (x - \frac{π}{2}) = 1 - sin (x - \frac{3 π}{2})

7 (sin (x)) (cos (x)) + cos^{2} (x) = 1

2 sec (x) = tan (x) + cot (x)

What is the general solution for sin^2(x)+2cos(x)-2=0 ?
The general solution for sin^2(x)+2cos(x)-2=0 is x=2pin