What is the general solution for 1=cos(t) ?

The general solution for 1=cos(t) is t=2pin

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1=cos(t)

1 = cos (t)

t = 2 πn

Degrees

t = 0^{\circ} + 36 0^{\circ} n

Solution steps

1 = cos (t)

Switch sides

cos (t) = 1

General solutions for

cos (t) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = 0 + 2 πn

t = 0 + 2 πn

Solve

t = 0 + 2 πn : t = 2 πn

t = 0 + 2 πn

0 + 2 πn = 2 πn

t = 2 πn

t = 2 πn

cos (2 x) + 2 = sin (x)

tan (t) = \frac{8}{15}

3 cos^{2} (x) - 6 cos (x) = - 3

3 sin (x) + 4 cos (x) - 5 = 0

3 sin (θ) + 3 = sin (θ)

What is the general solution for 1=cos(t) ?
The general solution for 1=cos(t) is t=2pin