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شائع >

sin(x)+cos(x)*cot(x)=2

الحلّ

sin (x) + cos (x) \cdot cot (x) = 2

الحلّ

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

+1

درجات

x = 3 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n

خطوات الحلّ

sin (x) + cos (x) cot (x) = 2

من الطرفين

2

اطرح

sin (x) + cos (x) cot (x) - 2 = 0

sin, cos :

عبّر بواسطة

- 2 + sin (x) + cos (x) cot (x)

cot (x) = \frac{cos ( x )}{sin ( x )}

:Use the basic trigonometric identity

= - 2 + sin (x) + cos (x) \frac{cos ( x )}{sin ( x )}

- 2 + sin (x) + cos (x) \frac{cos ( x )}{sin ( x )}

بسّط:

\frac{- 2 sin ( x ) + sin ^{2} ( x ) + cos ^{2} ( x )}{sin ( x )}

- 2 + sin (x) + cos (x) \frac{cos ( x )}{sin ( x )}

cos (x) \frac{cos ( x )}{sin ( x )} = \frac{cos ^{2} ( x )}{sin ( x )}

cos (x) \frac{cos ( x )}{sin ( x )}

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{cos ( x ) cos ( x )}{sin ( x )}

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

1 + 1 = 2 :

اجمع الأعداد

= cos^{2} (x)

= \frac{cos ^{2} ( x )}{sin ( x )}

= - 2 + sin (x) + \frac{cos ^{2} ( x )}{sin ( x )}

2 = \frac{2 sin ( x )}{sin ( x )}, sin (x) = \frac{sin ( x ) sin ( x )}{sin ( x )}

:حوّل الأعداد لكسور

= - \frac{2 sin ( x )}{sin ( x )} + \frac{sin ( x ) sin ( x )}{sin ( x )} + \frac{cos ^{2} ( x )}{sin ( x )}

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

:بما أنّ المقامات متساوية، اجمع البسوط

= \frac{- 2 sin ( x ) + sin ( x ) sin ( x ) + cos ^{2} ( x )}{sin ( x )}

- 2 sin (x) + sin (x) sin (x) + cos^{2} (x) = - 2 sin (x) + sin^{2} (x) + cos^{2} (x)

- 2 sin (x) + sin (x) sin (x) + cos^{2} (x)

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

1 + 1 = 2 :

اجمع الأعداد

= sin^{2} (x)

= - 2 sin (x) + sin^{2} (x) + cos^{2} (x)

= \frac{- 2 sin ( x ) + sin ^{2} ( x ) + cos ^{2} ( x )}{sin ( x )}

= \frac{- 2 sin ( x ) + sin ^{2} ( x ) + cos ^{2} ( x )}{sin ( x )}

\frac{cos ^{2} ( x ) + sin ^{2} ( x ) - 2 sin ( x )}{sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos^{2} (x) + sin^{2} (x) - 2 sin (x) = 0

Rewrite using trig identities

cos^{2} (x) + sin^{2} (x) - 2 sin (x)

cos^{2} (x) + sin^{2} (x) = 1

:فعّل نطريّة فيتاغوروس

= - 2 sin (x) + 1

- 2 sin (x) + 1 = 0

انقل

1

إلى الجانب الأيمن

- 2 sin (x) + 1 = 0

من الطرفين

1

اطرح

- 2 sin (x) + 1 - 1 = 0 - 1

بسّط

- 2 sin (x) = - 1

- 2 sin (x) = - 1

- 2

اقسم الطرفين على

- 2 sin (x) = - 1

- 2

اقسم الطرفين على

\frac{- 2 sin ( x )}{- 2} = \frac{- 1}{- 2}

بسّط

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2}

sin (x) = \frac{1}{2} :

حلول عامّة لـ

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{5 π}{6} + 2 πn

رسم

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