What is the general solution for cos^2(x)+cos(-x)=0 ?

The general solution for cos^2(x)+cos(-x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=pi+2pin

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cos^2(x)+cos(-x)=0

cos^{2} (x) + cos (- x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = π + 2 πn

Solution steps

cos^{2} (x) + cos (- x) = 0

Rewrite using trig identities

cos (x) + cos^{2} (x) = 0

Solve by substitution

cos (x) = 0, cos (x) = - 1

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = π + 2 πn

x, ln (y) + y^{2} = - cos (x)

tan (x) = 1.33

cot (x) = 5

8^{2} = 1 4^{2} + 1 9^{2} - 2 (14) (19) cos (C)

2 sin^{2} (x) = 3 cos (x) + 3

What is the general solution for cos^2(x)+cos(-x)=0 ?
The general solution for cos^2(x)+cos(-x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin,x=pi+2pin