What is the general solution for 2sin(2x+15)=1 ?

The general solution for 2sin(2x+15)=1 is x=180n+7.5,x=180n+67.5

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2sin(2x+15)=1

2 sin (2 x + 1 5^{\circ}) = 1

x = 18 0^{\circ} n + 7. 5^{\circ}, x = 18 0^{\circ} n + 67. 5^{\circ}

Solution steps

2 sin (2 x + 1 5^{\circ}) = 1

Divide both sides by

2

sin (2 x + 1 5^{\circ}) = \frac{1}{2}

General solutions for

sin (2 x + 1 5^{\circ}) = \frac{1}{2}

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n, 2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n

Solve

2 x + 1 5^{\circ} = 3 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 7. 5^{\circ}

Solve

2 x + 1 5^{\circ} = 15 0^{\circ} + 36 0^{\circ} n : x = 18 0^{\circ} n + 67. 5^{\circ}

x = 18 0^{\circ} n + 7. 5^{\circ}, x = 18 0^{\circ} n + 67. 5^{\circ}

2 - 2 sin^{2} (x) = cos (x)

tan (x) + 3 = sec (x)

16 sec^{2} (θ) - 1 = 0

4 cos (x) - 1 = 5

cos (4 y) = 2 cos (2 y) - 1

What is the general solution for 2sin(2x+15)=1 ?
The general solution for 2sin(2x+15)=1 is x=180n+7.5,x=180n+67.5