What is the general solution for 9+sin^2(x)=10 ?

The general solution for 9+sin^2(x)=10 is x= pi/2+2pin,x=(3pi)/2+2pin

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9+sin^2(x)=10

9 + sin^{2} (x) = 10

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

9 + sin^{2} (x) = 10

Solve by substitution

sin (x) = 1, sin (x) = - 1

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

tan^{2} (3 x) = 1

3 + 3 sin (θ) = 0

cos (2 x) = \frac{( 8 k - 7 )}{7}

cos^{2} (x) - 3 sin (2 x) + sin^{2} (x) + 2 sin^{2} (2 x) = 0

2 cos^{2} (x) + sin (- x) - 1 = 0

What is the general solution for 9+sin^2(x)=10 ?
The general solution for 9+sin^2(x)=10 is x= pi/2+2pin,x=(3pi)/2+2pin